(u-3)^2=2u^2+4u+33

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Solution for (u-3)^2=2u^2+4u+33 equation: 



(u-3)^2=2u^2+4u+33

We move all terms to the left:

(u-3)^2-(2u^2+4u+33)=0

We get rid of parentheses

-2u^2+(u-3)^2-4u-33=0

We add all the numbers together, and all the variables

-2u^2-4u+(u-3)^2-33=0

We move all terms containing u to the left, all other terms to the right

-2u^2-4u+(u-3)^2=33

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